If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-32x+256=220
We move all terms to the left:
4x^2-32x+256-(220)=0
We add all the numbers together, and all the variables
4x^2-32x+36=0
a = 4; b = -32; c = +36;
Δ = b2-4ac
Δ = -322-4·4·36
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-8\sqrt{7}}{2*4}=\frac{32-8\sqrt{7}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+8\sqrt{7}}{2*4}=\frac{32+8\sqrt{7}}{8} $
| 5k+3+2=-15 | | 4(9+1/7x)=296/7 | | 3/8+1/2=6(1/16f-3) | | 3s-11=s+11 | | 30(8X75)+11t=400 | | 7.00p+1.50=11.50 | | 4(1x+6)=2-6(1x+3) | | 6(4/9-5x)=-64/3 | | ×-3/5-4-3x/3=2/15 | | -9x-1=-9x² | | -6-(-2n)=3n-(6+5 | | 4+7x=-20+30x | | ×-3-4-3x=2 | | 8x-(2x-11)=35 | | 7(1x+6)=42 | | 8e–17=19–4e | | 4+7x=-20= | | (X-12)3x-12=3 | | 7x+10=-2(1x-5) | | t-6+9t=3(4t-6) | | -1/2(2x+5)=-5/3 | | Y=2(y+5)-7 | | 4(4-w=3(2w+2) | | 4n+6-2n=2n+4 | | 3(6+7x)=-45 | | -18+2=-4(x+5) | | 15=2x(4) | | X+10+4x+20=180 | | -100=2(7x-6) | | 7c=43 | | 1/2(5x-2/3)=113/66 | | 9(m+6)=-27 |